Can Chimaev become a double champ?

[C0NCH3TO]

Can he destroy Usman and Israel?

 

[Mahkor]

He could finish both Usman and Izzy on the same night.

 

[AssassinFacedBaby]

Shertard at it again

 

[C0NCH3TO]

Shertard at it again

I am asking, bruh.

 

[SirKratos]

Shertard at it again

This. He becomes a triple champ not double!

 

[Usssssyyyy]

He could finish both Usman and Izzy on the same night.

Within 5 mins he could beat both.

 

[SKITZADACTYL]

no and no.


we get it, you guys think it's funny but nah stop.

 

[websurfer]

Only in a world where Jarel Meershart poses problems for Usman and Israel Adesanya. He doesn't.

 

[No Skill Gap]

He could.

But he still hasn't faced a top 10 guy in either division let alone a champion level guy. Now he gets another stepping stone, a top 8-12 guy I'd say. At least this proves he's way more legit than Sean O'Malley.

 

[WMMA]

He could finish both Usman and Izzy on the same night.

He would finish them together, with one punch

 

[C0NCH3TO]

no and no.


we get it, you guys think it's funny but nah stop.

its funny lets face it!

 

[aashmore]

Let’s see him against a legit fighter first

 

[SKITZADACTYL]

its funny lets face it!

mmmmmm nah.

 

[PlayTheGame]

Yes. It’s kinda obvious at this point. Double champ with multiple defences in each div is the least I expect of him.

 

[Nobru]

Can he destroy Usman and Israel?

havent seen enough of him.
wanna see him walk forward x Costa or Romero.

 

[SaigeVanZant]

He would finish them together, with one punch

One arm behind his back and feet shackled

 

[Ch31ck]

What has Khamzat shown that proves he can beat Costa, Romero, Whittaker, Cannonier, or any of the top guys at MW? Or even at WW. Can he beat Colby? Maybe. But we haven't seen him beat anyone good yet.

 

[Wonderfight]

We've still seen nothing of him. That's like asking can Sean O'Malley be double champ after he ko-ed Wineland. Maybe, maybe not. Probably not.

 

[DarthChen731]

At the same time, prob

 

[KID Yamamoto]

Give him some ranked guys first.