- Joined
- Dec 29, 2003
- Messages
- 3,379
- Reaction score
- 0
Last comp I went in was like this (only showing 6 guys not the full 26).
Round 1.
F1 Bye
F2
Vs
F3
F4
Vs
F5
F6 bye.
Round 2
F1
Vs
Winner fo F2 and F3
Winner of F4 and F5
Vs
F6.
Its not like this cost of me anything results wise I just think it would be a fairer system if the fighters with Byes had to face each other ie have to face a fresh opponent instead of guys who have already fought.
(yes I know they aren't really fights it was just easier to say it that way)
This is the way it HAS to be. Your first example is worse because basically you have four fighters in the top half of the bracket, the other two with the bottom half all to themselves. You "drew it up" right in this example but it might be better understood if you had the actual seeds correct. It should look like this...
Round 1.
F1 vs F8 (no F8!) Bye
F5 Vs F4
----------------------|
F3 Vs F6
F2 vs F7 (no F7!) bye
Now, here's what I'm talking about with the beauty of the math. "Add up" the seeds for those matches. They are all equal to 9. But it's not just 9. It's B+1 where B=the size of the bracket. This works for ALL 'normal' brackets. A 16 person bracket? Add the seeds for each first round match up and they should all equal 17. But to be honest it's not just (B+1). It's actually ST=[B/2^(r-1)]+1 (Stick with me here) where ST is the seed total, B is the initial size of the bracket, and r is the round. So...16 person bracket, B=16...first round, r=1...
ST=[16/2^(1-1)]+1 1-1=0 and anything to the "zero" power equals 1
ST=[16/1]+1
ST=17 for first round matches
Round 2
ST=[16/2^(2-1)]+1 2-1=1 and anything to the power of 1 equals itself
ST=[16/2]+1
ST=9 for second round matches
Round 3
ST=[16/2^(3-1)]+1
ST=[16/4]+1
ST=5 for third round matches
Round 4 (Finals)
ST=[16/2^(4-1)]+1
ST=[16/8]+1
ST=3 for third round matches
I must also note that this is advancing the highest seed in each match, but even if the 16 beats the 1 you just advance them as the new 1. This is more for seeing how the brackets "make sense" than how an actual brackets develops in "real life". If you understand the mechanism behind how the are created and are supposed to work, you can figure out a bracket of any size!
Another neat number, the total number of matches (for single elimination bracket) is N-1 where N equals the number of competitors. Now this one works REGARDLESS of how many competitor are in the bracket. 14 competitors...13 matches. 16 competitors...15 matches. 7 competitors...6 matches.
Man, there's more, but I gots to go!