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Physics Question (Momentum and Impulse)

Katipwnan

"I love my motorola."
@purple
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Asshole pitches a baseball with a mass of 0.20 kg. The ball arrives at home plate with a speed of 40 m/s and is batted straight back to Asshole with a return speed of 60 m/s. If the bat is in contact with the ball for 0.050 s. What is the impulse experienced by the ball?

Impulse formula=(Mass)(Change in Velocity)/Time
=(.20kg)(60-40)/0.50s
=80

Answer is supposed to be 20 N*s
 
dude ur formulas wrong to begin with

impulse is mass times change in velocity

imp1.gif
 
f=ma

f=mΔv/t

f*t=mΔv
 
dude ur formulas wrong to begin with

impulse is mass times change in velocity

imp1.gif
His formula looks basically correct. He's dividing both sides by the change in Time to determine the Force.
 
His formula looks basically correct. He's dividing both sides by the change in time.

that not impulse. thats just force or mass times change in velocity

also he used 0.5 seconds instead of 0.05s.
 
is this a space time continuum problem or a
flux capacitor issue?
and can we go back in time far enough to when mary steenburgen was actrually kinda hot?
 
Should be (60+40) for change in velocity because the direction is reversed. The ball has to go from 60 to 0 then to 40 in the opposite direction.
Also the time should be 0.05s

not to mention the formula is to find the force not the impulse
 
that not impulse. thats just force or mass times change in velocity

also he used 0.5 seconds instead of 0.05s.
That's just a typo in his typed equation; he gets 80N using 0.05s (and 8N using 0.5s).
 
Should be (60+40) for change in velocity because the direction is reversed. The ball has to go from 60 to 0 then to 40 in the opposite direction.
Also the time should be 0.05s

not to mention the formula is to find the force not the impulse

u da man! velocity is a vector with magnitude & direction lol (i dont think the time matters in the calculation)

dam been to long since ive done physics
 
I think there should be a Mayberry Science Thread Sticky here where theories
and notions that might prove to be extremely important but no one cares about could be discussed ad nauseum.
 
I think there should be a Mayberry Science Thread Sticky here where theories
and notions that might prove to be extremely important but no one cares about could be discussed ad nauseum.

make it happen tachy
 
I misread earlier and thought he was asking for the force.

Okay, so let's sum it up here for the TS:

imp1.gif


Force * (Change of Time) = Mass * (Change of Velocity)
Force = Mass * (Change of Velocity) / (Change of Time)
Force = .20 kg * (40 m/s + 60 m/s) / 0.05 s
Force = 400 N

Impulse = Force * (Change of Time)
Impulse = 400 N * 0.05 s
Impulse = 20 N
 
If a man you've never met before suddenly buys you flowers, that's impulse.

[YT]Oj9lqpLmSac[/YT]
 
Asshole pitches a baseball with a mass of 0.20 kg. The ball arrives at home plate with a speed of 40 m/s and is batted straight back to Asshole with a return speed of 60 m/s. If the bat is in contact with the ball for 0.050 s. What is the impulse experienced by the ball?

Impulse formula=(Mass)(Change in Velocity)/Time
=(.20kg)(60-40)/0.50s
=80

Answer is supposed to be 20 N*s

Do your own homework. Smart guys on Sherdog but you're playing Russian Roulette counting on any to answer altruistically.


whoa, who is Asshole?
American League or National League?

I'm assuming American League as:

First Base: Who.
Second Base: What.
Third Base: I Don't Know.
Left field: Why.
Center field: Because.
Pitcher: Tomorrow.
Catcher: Today.
Shortstop: I Don't Give a Darn.
Designated Hitter: Asshole.
 
I misread earlier and thought he was asking for the force.

Okay, so let's sum it up here for the TS:

imp1.gif


Force * (Change of Time) = Mass * (Change of Velocity)
Force = Mass * (Change of Velocity) / (Change of Time)
Force = .20 kg * (40 m/s + 60 m/s) / 0.05 s
Force = 400 N

Impulse = Force * (Change of Time)
Impulse = 400 N * 0.05 s
Impulse = 20 N

Ok. I get it now. Since the position of the ball at Asshole is the start of the ball which is 40 m/s, the ball comes back to asshole at -60 m/s. So the change in velocity is (40 m/s-(-60m/s))=100 m/s which I fucked up on and didn't apply the impulse formula correctly. Thank you for clearing it up.
 
Ok. I get it now. Since the position of the ball at Asshole is the start of the ball which is 40 m/s, the ball comes back to asshole at -60 m/s. So the change in velocity is (40 m/s-(-60m/s))=100 m/s which I fucked up on and didn't apply the impulse formula correctly. Thank you for clearing it up.
No prob; credit to our boys Zack Ryder and Katsumi Yamada for their help as well. Spent countless sleepless nights trying to complete physics/statics/fluid mechanics assignments as well, so I feel your pain!
 
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