Another Math Question

[Kanuck99]

@rj144

 

[syct23]

= Fuck Off clippy

 

[Jim Cozad Jr.]

Lol, literally just read this on yahoo...the article claimed both 16 and 1 could be correct...

 

[rj144]

@rj144

16, but for my equation it's 4!!

 

[Phr3121]

16

 

[Reyesnuthugr]

16, but for my equation it's 4!!

I used to think math was hard. But then I learned a little trick my professor taught me.
He said "If you're in doubt, just go with 4"

 

[Phr3121]

 

[Kanuck99]

 

[Mondo Freaks]

tree fiddy

 

[Hans Gercmiov]

How the fuck is it 16 and not 1

 

[rj144]

How the fuck is it 16 and not 1

(8/2)(2+2)

 

[Post 2 Decision]

How the fuck is it 16 and not 1

Well you definitely do the (2+2) first

So then it becomes
8 / 2 x 4

And just depends if you divide or multiply first

4 x 4

Or

8 / 8

 

[Hans Gercmiov]

Well you definitely do the (2+2) first

So then it becomes
8 / 2 x 4

And just depends if you divide or multiply first

4 x 4

Or

8 / 8

I understand how they reached that solution, but I've never heard of division before multiplication.

 

[Tol]

Follow the PEMDAS order of operations.
Calculate within parentheses (2+2) : 4
= 8 ÷ 2 * 4
Multiply and divide (left to right) 8 ÷ 2 * 4 : 16
= 16

If it was written 8 over 2(2+2)
Then 2+2 = 4
2*4 = 8
8 over 8 = 1

Now level up and solve this first year college algebra equation: √(x+2) + √(3x+7) = 1

 

[Deleted member 220895]

16, but only because I don't want to learn another way to do math. I don't need more math in my life.

 

[Post 2 Decision]

I understand how they reached that solution, but I've never heard of division before multiplication.

In school here we learn BEDMAS

Brackets Exponents Division Multiplication Addition Subtraction

However division and multiplication should be level and done left to right (as well as addition grouped with subtraction)

 

[rj144]

I understand how they reached that solution, but I've never heard of division before multiplication.

It doesn't matter when you do multiplication or division.

(9*3)/3 = 9

You can do multiplication first and then divide:

27/3 = 9

or do division first and multiply:

9/3*3 = 3*3 = 9

or

9*3/3 = 9

 

[MikeMcMann]

You always do the brackets first (2+2) = 4

Then you do multiplication and division in the order they come so 8 divided 2 times 4 = 16

You DO NOT skip over the 8 and do the 2 times 4 first to get 8 so that you end up with 8 divide 8. Why would you skip over the 8 first? Just because the 4 is in brackets and nearer to the 2??? NO. There is no rule for that.

How the fuck is it 16 and not 1

Well you definitely do the (2+2) first

So then it becomes
8 / 2 x 4

And just depends if you divide or multiply first

4 x 4

Or

8 / 8

 

[rj144]

Follow the PEMDAS order of operations.
Calculate within parentheses (2+2) : 4
= 8 ÷ 2 * 4
Multiply and divide (left to right) 8 ÷ 2 * 4 : 16
= 16

If it was written 8 over 2(2+2)
Then 2+2 = 4
2*4 = 8
8 over 8 = 1

Now level up and solve this first year college algebra equation: √(x+2) + √(3x+7) = 1

x = -2

 

[rj144]

You always do the brackets first (2+2) = 4

Then you do multiplication and division in the order they come so 8 divided 2 times 4 = 16

You DO NOT skip over the 8 and do the 2 times 4 first to get 8 so that you end up with 8 divide 8. Why would you skip over the 8 first? Just because the 4 is in brackets and nearer to the 2??? NO. There is no rule for that.

Doesn't matter the order of multiplication or division.